1276. Number of Burgers with No Waste of Ingredients

leetcode medium

#csharp#leetcode#medium

Task

Даны два целых числа tomatoSlices и cheeseSlices. Ингредиенты разных бургеров таковы: Jumbo Burger: 4 ломтика помидора и 1 ломтик сыра. Small Burger: 2 ломтика помидора и 1 ломтик сыра. Верните [total_jumbo, total_small] так, чтобы количество оставшихся tomatoSlices было равно 0, а количество оставшихся cheeseSlices было равно 0. Если невозможно сделать так, чтобы оставшиеся tomatoSlices и cheeseSlices были равны 0, верните [].

Пример:

Input: tomatoSlices = 16, cheeseSlices = 7

Output: [1,6]

C# solution

matched/original

public class Solution {
    public IList<int> NumOfBurgers(int tomatoSlices, int cheeseSlices) {
        if (tomatoSlices % 2 != 0 || tomatoSlices < 2 * cheeseSlices || tomatoSlices > 4 * cheeseSlices) {
            return new List<int>();
        }
        int total_jumbo = (tomatoSlices - 2 * cheeseSlices) / 2;
        int total_small = cheeseSlices - total_jumbo;
        return new List<int> { total_jumbo, total_small };
    }
}

C++ solution

auto-draft, review before submit

#include <bits/stdc++.h>
using namespace std;

// Auto-generated C++ draft from the C# solution. Review containers, LINQ and helper types before submit.
class Solution {
public:
    public vector<int> NumOfBurgers(int tomatoSlices, int cheeseSlices) {
        if (tomatoSlices % 2 != 0 || tomatoSlices < 2 * cheeseSlices || tomatoSlices > 4 * cheeseSlices) {
            return new List<int>();
        }
        int total_jumbo = (tomatoSlices - 2 * cheeseSlices) / 2;
        int total_small = cheeseSlices - total_jumbo;
        return new List<int> { total_jumbo, total_small };
    }
}

Java solution

matched/original

public class Solution {
    public List<Integer> numOfBurgers(int tomatoSlices, int cheeseSlices) {
        if (tomatoSlices % 2 != 0 || tomatoSlices < 2 * cheeseSlices || tomatoSlices > 4 * cheeseSlices) {
            return new ArrayList<>();
        }
        int total_jumbo = (tomatoSlices - 2 * cheeseSlices) / 2;
        int total_small = cheeseSlices - total_jumbo;
        return Arrays.asList(total_jumbo, total_small);
    }
}

JavaScript solution

matched/original

var numOfBurgers = function(tomatoSlices, cheeseSlices) {
    if (tomatoSlices % 2 !== 0 || tomatoSlices < 2 * cheeseSlices || tomatoSlices > 4 * cheeseSlices) {
        return [];
    }
    let total_jumbo = (tomatoSlices - 2 * cheeseSlices) / 2;
    let total_small = cheeseSlices - total_jumbo;
    return [total_jumbo, total_small];
};

Python solution

matched/original

def numOfBurgers(tomatoSlices, cheeseSlices):
    if tomatoSlices % 2 != 0 or tomatoSlices < 2 * cheeseSlices or tomatoSlices > 4 * cheeseSlices:
        return []
    total_jumbo = (tomatoSlices - 2 * cheeseSlices) // 2
    total_small = cheeseSlices - total_jumbo
    return [total_jumbo, total_small]

Explanation

Algorithm

1⃣Проверьте, возможно ли решить задачу, убедившись, что tomatoSlices четно и находится в допустимых пределах.

2⃣Решите систему уравнений:

4J + 2S = tomatoSlices

J + S = cheeseSlices